3x^2+36x+88=4

Solution for 3x^2+36x+88=4 equation:

3x^2+36x+88=4

We move all terms to the left:

3x^2+36x+88-(4)=0

We add all the numbers together, and all the variables

3x^2+36x+84=0

a = 3; b = 36; c = +84;
Δ = b2-4ac
Δ = 362-4·3·84
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{2}}{2*3}=\frac{-36-12\sqrt{2}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{2}}{2*3}=\frac{-36+12\sqrt{2}}{6}
$